Here is the Bitch of All Riddle games , I know no person that has beaten it , farthest I have gotten was where you have to answer some weird anagram, i think we just guessed letters and for some reason some letters we guessed appeared on the quest..pretty weird i must say. This is the hardest game I have ever tried >.> My friends beaten T.M. Riddles , Riddlemaster , Not Just Another Warcraft Map. But this one is just a bitch.
Request: I need the answers for all riddles
Note: Some of the answers you have to do something other than just type text
Note2: Please number than, and if isn't one of those text ones , explain what we have to do.
Note3: This map isnt the type where you just glimpse and get the answers from the triggers >.> you really need to look closely.
Link: http://www.epicwar.com/maps/7910/
The Bitch of All Riddles
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The Bitch of All Riddles
Eh I changed Accounts On USEast find me under [haven't made a new acc yet] I'll make new maps soon.
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Re: The Bitch of All Riddles
What's with you and the many riddles are you like in some riddle clan lolz?
Well here you go. Could only find so many even played the real game a bit.
Well here you go. Could only find so many even played the real game a bit.
You do not have the required permissions to view the files attached to this post.
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Re: The Bitch of All Riddles
Rofl I had haxx0red that map in one game, when people were like WTF WHAT DO WE DO... WinMPQ - war3map.j, and I got all of the answers. All of the people thought I was super intelligent lol.
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Re: The Bitch of All Riddles
OMG WOW THANKS , wut happnned to the blank ones?
Eh I changed Accounts On USEast find me under [haven't made a new acc yet] I'll make new maps soon.
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Re: The Bitch of All Riddles
When I deencypted they still didn't make sence, also note that lvl 15 isnt just southpark.Draike wrote:OMG WOW THANKS , wut happnned to the blank ones?
Supposedly HINDYhat deencrypted them all easily with no problems so you can ask him and hope he wasn't lieing.HINDYhat wrote:Rofl I had haxx0red that map in one game, when people were like WTF WHAT DO WE DO... WinMPQ - war3map.j, and I got all of the answers. All of the people thought I was super intelligent lol.
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Re: The Bitch of All Riddles
set udg_strings02[1]="40256712252236"
set udg_strings02[2]="293227"
set udg_strings02[3]="5649878513548223"
set udg_strings02[4]="651452332102551"
set udg_strings02[5]="2210282914272518141214"
set udg_strings02[6]="5120154987546123485"
set udg_strings02[7]="197543132452151"
set udg_strings02[8]="25181229302714"
set udg_strings02[9]="221025"
set udg_strings02[10]="1221243013"
set udg_strings02[11]="4042414040424040404142404042404041414040"
set udg_strings02[12]="1524302329101823362415363424302917"
set udg_strings02[13]="96412348213244512215423"
set udg_strings02[14]="2114311421361524302729141423"
set udg_strings02[15]="282430291725102720"
set udg_strings02[16]="851346543216987543213"
set udg_strings02[17]="654552213412140402152543"
set udg_strings02[18]="121023132114"
set udg_strings02[19]="28171825"
set udg_strings02[20]="8978558531215152014"
set udg_strings02[21]="25102710132433"
set udg_strings02[22]="112718231614273624153622102528"
set udg_strings02[23]="96589778451258542341"
Those are all the answers, encrypted. There are 2 decryption functions:
function CR takes string a returns string
local integer la=1
local integer lb
local integer t=1
local string array p
local string r=""
loop
exitwhen la>StringLength(a)/2
set p[la]=SubStringBJ(a,t,t+1)
set t=t+2
set lb=10
loop
exitwhen lb>47
if p[la]==I2S(lb)then
set r=r+udg_strings05[lb]
endif
set lb=lb+1
endloop
set la=la+1
endloop
return r
endfunction
function Cs takes string a returns string
local integer la=1
local integer lb
local string array s
local string r=""
loop
exitwhen la>StringLength(a)
set s[la]=SubStringBJ(a,la,la)
set lb=10
loop
exitwhen lb>47
if s[la]==udg_strings05[lb]then
set r=r+I2S(lb)
endif
set lb=lb+1
endloop
set la=la+1
endloop
return r
endfunction
Those refer to a character map:
set udg_strings05[10]="a"
set udg_strings05[11]="b"
set udg_strings05[12]="c"
set udg_strings05[13]="d"
set udg_strings05[14]="e"
set udg_strings05[15]="f"
set udg_strings05[16]="g"
set udg_strings05[17]="h"
set udg_strings05[18]="i"
set udg_strings05[19]="j"
set udg_strings05[20]="k"
set udg_strings05[21]="l"
set udg_strings05[22]="m"
set udg_strings05[23]="n"
set udg_strings05[24]="o"
set udg_strings05[25]="p"
set udg_strings05[26]="q"
set udg_strings05[27]="r"
set udg_strings05[28]="s"
set udg_strings05[29]="t"
set udg_strings05[30]="u"
set udg_strings05[31]="v"
set udg_strings05[32]="w"
set udg_strings05[33]="x"
set udg_strings05[34]="y"
set udg_strings05[35]="z"
set udg_strings05[36]=" "
set udg_strings05[37]="-"
set udg_strings05[38]="9"
set udg_strings05[39]="0"
set udg_strings05[40]="1"
set udg_strings05[41]="2"
set udg_strings05[42]="3"
set udg_strings05[43]="4"
set udg_strings05[44]="5"
set udg_strings05[45]="6"
set udg_strings05[46]="7"
set udg_strings05[47]="8"
Example. Level 2's answer is -twr.
twr is the string the game takes. The string answer from the game is: set udg_strings02[2]="293227"
Use the decryption methods until you get a proper answer. 293227. Check the character map, 29 = t, 32 = w, 27 = r
-twr is the same as 293227 through the encryption....
Have fun...
set udg_strings02[2]="293227"
set udg_strings02[3]="5649878513548223"
set udg_strings02[4]="651452332102551"
set udg_strings02[5]="2210282914272518141214"
set udg_strings02[6]="5120154987546123485"
set udg_strings02[7]="197543132452151"
set udg_strings02[8]="25181229302714"
set udg_strings02[9]="221025"
set udg_strings02[10]="1221243013"
set udg_strings02[11]="4042414040424040404142404042404041414040"
set udg_strings02[12]="1524302329101823362415363424302917"
set udg_strings02[13]="96412348213244512215423"
set udg_strings02[14]="2114311421361524302729141423"
set udg_strings02[15]="282430291725102720"
set udg_strings02[16]="851346543216987543213"
set udg_strings02[17]="654552213412140402152543"
set udg_strings02[18]="121023132114"
set udg_strings02[19]="28171825"
set udg_strings02[20]="8978558531215152014"
set udg_strings02[21]="25102710132433"
set udg_strings02[22]="112718231614273624153622102528"
set udg_strings02[23]="96589778451258542341"
Those are all the answers, encrypted. There are 2 decryption functions:
function CR takes string a returns string
local integer la=1
local integer lb
local integer t=1
local string array p
local string r=""
loop
exitwhen la>StringLength(a)/2
set p[la]=SubStringBJ(a,t,t+1)
set t=t+2
set lb=10
loop
exitwhen lb>47
if p[la]==I2S(lb)then
set r=r+udg_strings05[lb]
endif
set lb=lb+1
endloop
set la=la+1
endloop
return r
endfunction
function Cs takes string a returns string
local integer la=1
local integer lb
local string array s
local string r=""
loop
exitwhen la>StringLength(a)
set s[la]=SubStringBJ(a,la,la)
set lb=10
loop
exitwhen lb>47
if s[la]==udg_strings05[lb]then
set r=r+I2S(lb)
endif
set lb=lb+1
endloop
set la=la+1
endloop
return r
endfunction
Those refer to a character map:
set udg_strings05[10]="a"
set udg_strings05[11]="b"
set udg_strings05[12]="c"
set udg_strings05[13]="d"
set udg_strings05[14]="e"
set udg_strings05[15]="f"
set udg_strings05[16]="g"
set udg_strings05[17]="h"
set udg_strings05[18]="i"
set udg_strings05[19]="j"
set udg_strings05[20]="k"
set udg_strings05[21]="l"
set udg_strings05[22]="m"
set udg_strings05[23]="n"
set udg_strings05[24]="o"
set udg_strings05[25]="p"
set udg_strings05[26]="q"
set udg_strings05[27]="r"
set udg_strings05[28]="s"
set udg_strings05[29]="t"
set udg_strings05[30]="u"
set udg_strings05[31]="v"
set udg_strings05[32]="w"
set udg_strings05[33]="x"
set udg_strings05[34]="y"
set udg_strings05[35]="z"
set udg_strings05[36]=" "
set udg_strings05[37]="-"
set udg_strings05[38]="9"
set udg_strings05[39]="0"
set udg_strings05[40]="1"
set udg_strings05[41]="2"
set udg_strings05[42]="3"
set udg_strings05[43]="4"
set udg_strings05[44]="5"
set udg_strings05[45]="6"
set udg_strings05[46]="7"
set udg_strings05[47]="8"
Example. Level 2's answer is -twr.
twr is the string the game takes. The string answer from the game is: set udg_strings02[2]="293227"
Use the decryption methods until you get a proper answer. 293227. Check the character map, 29 = t, 32 = w, 27 = r
-twr is the same as 293227 through the encryption....
Have fun...
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Re: The Bitch of All Riddles
The one's that only use those encytions have alrady been answered, unfotunately a few of them get new data so you'd have to look up the specific trigger also.
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Re: The Bitch of All Riddles
yes... they were, they just are obviously unencrypted ingame...HINDYhat wrote:Holy... lol in the version I played the answers weren't encrypted :S
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Re: The Bitch of All Riddles
Well i'll take it that all this was good enough for ya, if not tell me.